Grade 12 Differential Calculus: How to Identify the Question Type
Differential calculus is Grade 12-only content. Questions test finding derivatives (from first principles or rules), using derivatives to find gradients and equations of tangents, and sketching cubic graphs by finding stationary points and points of inflection.
Type 1: Finding the derivative from first principles
Trigger words: "From first principles", "using the definition of the derivative"
Trigger structure: The instruction explicitly says 'first principles', do NOT use the power rule here even if it would give the same answer.
Do not confuse with: The power rule: first principles requires the limit definition. Using the rule when first principles is specified earns zero.
Method (no numbers, just the steps)
- Write the definition: f'(x) = lim[h→0] [f(x + h) − f(x)] / h
- Substitute f(x + h) by replacing every x with (x + h)
- Expand and simplify the numerator, the h in the denominator must cancel
- Take the limit as h → 0
See the progression: same type, increasing difficulty
Type 2: Differentiation rules (power rule)
Trigger words: "Determine f'(x)", "Find dy/dx", "Differentiate"
Trigger structure: A polynomial, rational expression, or surd that can be rewritten as a sum of power terms.
Do not confuse with: First principles: use the rules unless 'first principles' is specified.
Method (no numbers, just the steps)
- Rewrite the function so every term is of the form ax^n
- Rewrite fractions: 1/x = x^(−1); surds: √x = x^(1/2)
- Apply: d/dx[ax^n] = anx^(n−1)
- Simplify: rewrite negative exponents as fractions if needed
See the progression: same type, increasing difficulty
Type 3: Gradient of a tangent and equation of a tangent
Trigger words: "Determine the gradient of the tangent", "Find the equation of the tangent at", "At which point is the gradient equal to"
Trigger structure: A curve and a specific point (or gradient value) are given. The question asks for the slope or equation of the line touching the curve at that point.
Method (no numbers, just the steps)
- Differentiate f(x) to get f'(x)
- Substitute the given x-value into f'(x) to find the gradient m
- Use y − y₁ = m(x − x₁) to write the tangent equation, where (x₁, y₁) is the point on the curve
See the progression: same type, increasing difficulty
Type 4: Cubic graph: stationary points and sketching
Trigger words: "Sketch the graph of", "Find the coordinates of the turning points", "Determine the x-values of the stationary points"
Trigger structure: A cubic function f(x) = ax³ + bx² + cx + d is given. You must find turning points, x-intercepts, and sketch.
Method (no numbers, just the steps)
- Find x-intercepts: factorise f(x), try synthetic division with rational root candidates
- Find stationary points: solve f'(x) = 0
- Determine nature: f''(x) > 0 at x₀ → local minimum; f''(x) < 0 at x₀ → local maximum
- Find y-values of stationary points by substituting back into f(x)
- Note the y-intercept: f(0)
See the progression: same type, increasing difficulty
Type 5: Applied calculus (optimisation and rate of change)
Trigger words: "Maximum volume", "minimum cost", "rate of change", "At what time is the velocity zero"
Trigger structure: A real-world scenario gives a formula. The question asks for a maximum or minimum value, or asks how fast something is changing.
Method (no numbers, just the steps)
- Write the quantity to optimise as a function of one variable
- Differentiate and set f'(x) = 0 to find the critical value
- Verify it is a maximum or minimum using f''(x) or by checking function values
- For rate of change: differentiate and substitute the given value of x or t
See the progression: same type, increasing difficulty
Words like determine and hence appear throughout this topic, see the instruction word glossary for full definitions.